Secα-cosα = Sinαtanα
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some properties of trigonometry used here
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Animesh282:
galat hai
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Hey....!!! here is ur answer..........
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To prove: secA - cosA = sinAtanA
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On taking L.H.S.,
secA - cosA
(1/cosA) - cosA {we know that,secA = 1/cosA}
(1-cos²A)/cosA
sin²A/cosA {we know that,1-cos²A = sin²A}
sinA*sinA/cosA
sinAtanA {we know that,sinA/cosA= tanA}
= R.H.S.
I hope it helps u..........
THANK YOU..........!!!!!!
☺️☺️☺️☺️✌️✌️✌️
__________________________
__________________________
To prove: secA - cosA = sinAtanA
------------------------_------------------------
On taking L.H.S.,
secA - cosA
(1/cosA) - cosA {we know that,secA = 1/cosA}
(1-cos²A)/cosA
sin²A/cosA {we know that,1-cos²A = sin²A}
sinA*sinA/cosA
sinAtanA {we know that,sinA/cosA= tanA}
= R.H.S.
I hope it helps u..........
THANK YOU..........!!!!!!
☺️☺️☺️☺️✌️✌️✌️
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