Math, asked by adikemallikarjuna78, 2 months ago

(secα.secβ+ tanα.tanβ)^2 -(secα·tanβ+ tanα.secβ)^2=

Answers

Answered by sharonsharon
0

Answer:

Prove the following statements. (tanalpha + cosec beta)^2 - (cotbeta - secalpha)^2 = 2tanalphacotbeta (cosec alpha + secbeta) .

Step-by-step explanation:

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