Question

Sec sq 2x =1-tan 2 x

Answer 1

sec²2x=1-tan2x
1+tan²2x=1-tan2x
tan²2x=-tan2x
∴tan2x=0 or tan 2x= -1 
tan2x=0 
⇒ 2x=$n \pi$
∴x=$n \pi$/2
again,
tan 2x= -1 
⇒2x=[tex]n \pi [/tex] - $\pi /4$
∴x=($(n \pi /8)$$n \pi /2$)-

Answer 2

I hope it will help u...