Question

sec square 45 degree minus cos square 45 degree minus sin square 30 degree minus sin square 60 degree ​

Answer 1

Answer:

1/2

Step-by-step explanation:

$\sec ^{2} 45 - \cos^{2} 45 - \sin^{2} 30 - \sin^{2} 60 \\ = \ { (\sqrt{2} )}^{2} - ( \frac{1}{ \sqrt{2} } )^{2} - ( \frac{1}{2} ) ^{2} - ( \frac{ \sqrt{3} }{2} ) ^{2} \\ = 2 - \frac{1}{2} - \frac{1}{4} - \frac{3}{4} \\ = \frac{8 - 2 - 1 - 3}{4} \\ = \frac{8 - 6}{4} \\ = \frac{2}{4} \\ = \frac{1}{2}$