sec square 60+cosec square 30
Answers
Answered by
8
Answer:
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Step-by-step explanation:
sin
2
30
∘
−tan
2
60
∘
+cosec
2
60
∘
+
cosec90
∘
6sec
2
45
∘
+cos60
∘
−tan
2
45
\cirs
=\frac{121}{12}=
12
121
Step-by-step explanation:
Given
sin ^ 2 30^\circ - tan^2 60^\circ +cosec^2 60^\circ+\frac{6sec^245^\circ}{cosec90^\circ} +cos 60^\circ - tan^2 45^\cirssin
2
30
∘
−tan
2
60
∘
+cosec
2
60
∘
+
cosec90
∘
6sec
2
45
∘
+cos60
∘
−tan
2
45
\cirs
= (\frac{1}{2} )^2-(\sqrt{3})^2+(\frac{2}{\sqrt {3 }})^2 + \frac{6(\sqrt{2} )^2}{1} +\frac{1}{2} -(1)^2=(
2
1
)
2
−(
3
)
2
+(
3
2
)
2
+
1
6(
2
)
2
+
2
1
−(1)
2
=\frac{1}{4} -3+\frac{4}{3} +\frac{12}{1} +\frac{1}{2}-1=
4
1
−3+
3
4
+
1
12
+
2
1
−1
=\frac{121}{12}=
12
121
Answered by
1
Answer:
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