Question

sec square 60+cosec square 30​

Answer 1

Answer:

Hope it helps pls mark me BRAINLIST

Step-by-step explanation:

sin

2

30

∘

−tan

2

60

∘

+cosec

2

60

∘

+

cosec90

∘

6sec

2

45

∘

+cos60

∘

−tan

2

45

\cirs

=\frac{121}{12}=

12

121

Step-by-step explanation:

Given

sin ^ 2 30^\circ - tan^2 60^\circ +cosec^2 60^\circ+\frac{6sec^245^\circ}{cosec90^\circ} +cos 60^\circ - tan^2 45^\cirssin

2

30

∘

−tan

2

60

∘

+cosec

2

60

∘

+

cosec90

∘

6sec

2

45

∘

+cos60

∘

−tan

2

45

\cirs

= (\frac{1}{2} )^2-(\sqrt{3})^2+(\frac{2}{\sqrt {3 }})^2 + \frac{6(\sqrt{2} )^2}{1} +\frac{1}{2} -(1)^2=(

2

1

)

2

−(

3

)

2

+(

3

2

)

2

+

1

6(

2

)

2

+

2

1

−(1)

2

=\frac{1}{4} -3+\frac{4}{3} +\frac{12}{1} +\frac{1}{2}-1=

4

1

−3+

3

4

+

1

12

+

2

1

−1

=\frac{121}{12}=

12

121

Answer 2

Answer:

hope it will be helpful ☺️

Mark me brainliest