Question

sec square ( 90 degree ) it is

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Answer 1

Answer:

hence prove

Step-by-step explanation:

L.H.S=sec^2(90-●)-1/cot^2(90-●)

AS we know sec^2(90-●)=cosec^2 90

and cot (90-●)= tan^2 90

=cosec^2 90- 1/tan^2 90

=cosec^2 90-cot^2 90

we know cosec^2 ● - cot^2 ● = 1

=1

therefore L.H.S=R.H.S