Question

sec square A - ( sin square A - 2 sin to the power 4 A / 2 cos to the power 4A - cos square A) = 1??

Answer 1

Sec2a - (sin2a [1-2sin2a])/(cos2a[2cos2a -1])
= sec2a - tan2a [1- 2sin2a]/[2cos2a -1]
= sec2a - tan2a [1- sin2a - sin2a]/ [cos2a + cos2a -1]
= sec2a - tan2a [ cos 2a - sin 2a]/[cos2a - sin2a]
= sec2a - tan2a *1
= sec2a - tan2a
= 1
I hope it's clear to you...

Answer 2

Step-by-step explanation:

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