Math, asked by danialkul, 7 months ago

sec square theta - 1 =
(A) tan square theta
(B) cot Square theta-1
(C) tan square theta+1
(D) cos square theta​

Answers

Answered by hdthebest95
0

Hola mate! Here is your answer!

Solution:

Using the identity

 {sec}^{2}  -  {tan}^{2}  = 1 \\  {sec}^{2}  - 1 =  {tan}^{2}

So answer is Tan^2 theta

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