sec square theta minus cos square /ø equal to sin square ø + tan square theta
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Step-by-step explanation:
According to trigonometric identities,
sin² A + cos² A = 1
here A is considered as ø
=> sin² ø + cos² ø = 1 ---------- (1)
And sec² A - tan² A = 1
here A is considered as theta
=> sec² theta - tan² theta = 1 ------------- (2)
From (1) & (2)
sin² ø + cos² ø = sec² theta - tan² theta
=> sin² ø + tan² theta = sec² theta - cos² ø
Hence proved
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