sec squared theta minus sin square theta upon 10 square theta is equal to cosec squared theta minus cos squared theta
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Answer:
Step-by-step explanation:
Sec²θ - Sin²θ/ Tan²θ = Cosec²θ - Cos²θ .
L.H.S:
Sec²θ - Sin²θ/ Tan²θ
= Sec²θ - Sin²θ / (Sin²θ/Cos²θ)
= Cos²θ(Sec²θ - Sin²θ) / Sin²θ
= Cos²θ * Sec²θ - Cos²θ * Sin²θ / Sin²θ
= 1 - Cos²θSin²θ / Sin²θ
= 1/Sin²θ - Cos²θSin²θ/Sin²θ
= Cosec²θ - Cos²θ
= R.H.S
Hence proved
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