Question

[secΘ+tanΘ-1]²/[tanΘ-secΘ+1]²

Answer 1

Step-by-step explanation:

hopefully may it helps you.........

Answer 2

Step-by-step explanation:

secø=1/cosø

tanø=sinø/cosø

(secø+tanø-1)²=(1/cosø+sinø/cosø-1)²

=(1+sinø/cosø - 1)²

(tanø-secø+1)=(sinø-1/cosø +1)²

(secø+tanø-1/tanø-secø+1)²=

(1+sinø-cosø/cosø/sin-1+cosø/cosø)²

(1+sinø-cosø/sinø+cosø-1)²=