sec - tan = 1/3, sec + tan =
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Answer:
secA + tanA = 1/3
multiplying both sides by (secA + tanA)
(secA+tanA)(secA−tanA) =(1/3) (secA−tanA)
(secA)^2−(tanA)^2 = (1/3) (secA−tanA)
1 = (1/3) (secA−tanA) since, (secA)^2−(tanA)^2 = 1
so (secA−tanA) = 3
Step-by-step explanation:
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