Question

secФ+tanФ=1/3 then secФ-tanФ=?

Answer 1

HELLO DEAR,

SEC THETA + TAN THETA = 1/3

[ Multiply Both side by (sec theta - tan theta)]


We get,

(Sectheta +tan theta )(sectheta-tan theta) = 1/3(sectheta -tan theta)


(Sec²theta -tan²theta )= 1/3(sectheta-tantheta)

[Sec²theta-tan²theta =1]


3=sectheta-tantheta



.
I HOPE ITS HELP YOU DEAR,
THANKS