(secθ+tanθ-1)(secθ-tanθ+1)= ?
Answers
Answered by
0
Answer:
L.H.S=
1+secθ+tanθ
1+secθ−tanθ
=
secθ+tanθ+1
secθ−tanθ+1
=
secθ+tanθ+1
secθ−tanθ+(sec
2
θ+tan
2
θ)
[∵sec
2
θ−tan
2
θ=1]
=
secθ+tanθ+1
secθ−tanθ+(secθ−tanθ)(secθ+tanθ)
=
(1+secθ+tanθ)
(secθ−tanθ)(1+secθ+tanθ)
=
cosθ
1
−
cosθ
sinθ
=
cosθ
1−sinθ
=R.H.S
Hence proved.
Answered by
0
Answer:
2tan theta
Step-by-step explanation:
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