Question

sec + tan -1/tan -sec+1​

Answer 1

Answer:

this is the formula

$\frac{ \sec( \alpha) + \tan( \alpha ) + 1 }{ \tan( \alpha ) - \sec( \alpha ) + 1} \\ \sec( \alpha ) = \frac{1}{ \cos( \alpha ) } \\ \tan( \alpha ) = \frac{ \sin( \alpha ) }{ \cos( \alpha )} \\ the \: put \: the \: value \: of \: sec \: and \: tan$

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