Question

sec θ – tan θ)² = ???​

Answer 1

${( \sec( \alpha ) - \tan( \alpha ) })^{2} \\ \\ { \sec( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + { \tan( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + 2 { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha )$