Math, asked by gopis131, 1 year ago

Sec ¤ + tan¤ = 2/3 then find the value of sec¤

Answers

Answered by mysticd
1
Hi ,

Here I am using A instead of angle symbol.

secA + tanA = 2/3 ----( 1 )

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we know the trigonometric identity,

sec² A - tan² A = 1

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( secA+ tanA )( secA - tanA ) = 1

2/3 ( secA - tanA ) = 1

secA - tanA = 3/2 ---( 2 )

add equations ( 1 ) & ( 2 ) we get ,

2secA = 2/3 + 3/2

2secA = ( 4 + 9 ) / 6

secA = 13/ 12

I hope this helps you.

: )
Answered by Anonymous
2
Hi,


Please see the attached file!


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