Sec ¤ + tan¤ = 2/3 then find the value of sec¤
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Answered by
1
Hi ,
Here I am using A instead of angle symbol.
secA + tanA = 2/3 ----( 1 )
**********************************
we know the trigonometric identity,
sec² A - tan² A = 1
*********************************†*****
( secA+ tanA )( secA - tanA ) = 1
2/3 ( secA - tanA ) = 1
secA - tanA = 3/2 ---( 2 )
add equations ( 1 ) & ( 2 ) we get ,
2secA = 2/3 + 3/2
2secA = ( 4 + 9 ) / 6
secA = 13/ 12
I hope this helps you.
: )
Here I am using A instead of angle symbol.
secA + tanA = 2/3 ----( 1 )
**********************************
we know the trigonometric identity,
sec² A - tan² A = 1
*********************************†*****
( secA+ tanA )( secA - tanA ) = 1
2/3 ( secA - tanA ) = 1
secA - tanA = 3/2 ---( 2 )
add equations ( 1 ) & ( 2 ) we get ,
2secA = 2/3 + 3/2
2secA = ( 4 + 9 ) / 6
secA = 13/ 12
I hope this helps you.
: )
Answered by
2
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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