Question

sec+tan=cosec+cot plzz

Answer 1

sec + tan =
1/cos + sin/cos =
1 + sin / cos =
cos / 1-sin =
cos ( 1 + sin ) / ( 1 -sin ) ( 1 + sin ) =
cos ( 1+ sin) / 1^2 - sin^2 =
cos ( 1 + sin ) / cos^2 =
1 + sin / cos =
1 / cos + sin / cos =
cosec + cot
Hence Proved.
please mark this answer as brainliest

Answer 2

$\huge \bf \red{ \mid{ \overline{ \underline{ANSWER}} \mid}}$


$\bf{QUESTION}$
you need to elaborate your question


sec+tan=cosec+1/cot

_____________________________


Sec+Tan=cosec+1/cot

LHS


$\huge \bf{ \frac{1}{cos} + \frac{sin}{cos}}$



$\huge \sf{ \frac{1 + sin}{cos}}$

$\bf{divide \: nominator \: and } \\ \bf{\: denominator \: by \: sin}$

$\huge \bf{ \frac{ \frac{1}{sin} + \frac{sin}{sin} }{ \frac{cos}{sin}} }$


$\huge \bf{ \frac{cosec + 1}{ \frac{cos}{sin}}}$

$\huge \bf{ \frac{cosec + 1}{cot}}$



$\huge \bf \orange{THANKS}$