sec+tan=χ.
тнєи fιи∂ тнє ναℓυє σf ѕє¢ αи∂ тαи... fυℓℓ. αиѕωєя ρℓѕѕ
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secø+tanø=x
secø+secø*sinø=x
secø(1+sinø)=x
secø=x/(1+sinø)
secø+tanø=x
tanø=x-sec
put the value of secø here
tanø=x-x/(1-sinø)
tanø=[x(1-sinø)-x]/(1-sinø)
tanø=x(1-sinø-1)/1-sinø
tanø= -x(sinø)/1-sinø
tanø=x(sinø)/sinø-1
secø+secø*sinø=x
secø(1+sinø)=x
secø=x/(1+sinø)
secø+tanø=x
tanø=x-sec
put the value of secø here
tanø=x-x/(1-sinø)
tanø=[x(1-sinø)-x]/(1-sinø)
tanø=x(1-sinø-1)/1-sinø
tanø= -x(sinø)/1-sinø
tanø=x(sinø)/sinø-1
Prathamattri2062:
if it helped please mark it brainliest
qиѕωєя ωяσиg нαιвнι
why the answer will be wrong
вυт. иι¢є
please tell what is wrong in this
so that i can correct my self
and so that i dont repeat the mistake in exam
please tell
ѕєи∂ ιт мє ну ѕσℓνιиg ιи υя ¢σρу
тнєи ι fσυи∂ υя fαℓтѕ
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