Question

secβ+tanβ=p then express the value of sinβ in terms p​

Answer 1

Answer:

secβ+tanβ=p

1/cosβ+sinβ/cosβ=p

multiply by cosβ

1 + sinβ = pcosβ

sinβ = pcosβ - 1

sinβ = p√(1-sin²β) -1

(sinβ+1)²/p² = 1-sin²β

(sin²β+1+2sinβ)/p² + sin²β = 1

sin²β+p²sin²β +1 +2sinβ = p²

sinβ(sinβ + p²sinβ + 2) = p² - 1