Math, asked by angolkargeetika, 3 months ago

sec-tan/sec+tan =1-2sec×tan+tan2

Answers

Answered by sucheta2007

0

Step-by-step explanation:

(sec-tan)(sec-tan)/(sec+tan)(sec-tan)

=(see-tan)²/(sec²-tan²)

=see²-2tan×sec+tan²

=1+tan²-2tan×sec+tan²

=1-2tan×sec+2tan²

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