Question

sec = tanº 0 + 3 tan sec? 0 +1​

Answer 1

Step-by-step explanation:

LHS =sec

6

θ

=(1+tan

2

θ)

3

=1+tan

6

θ+3tan

4

θ+3tan

2

θ

=1+tan

6

θ+3tan

2

θ(1+tan

2

θ)

=1+tan

6

θ+3tan

2

θsec

2

θ

=RHS