Question

√sec theta-1÷√sec theta +1 +√sec theta+1÷√sec theta-1=2​

Answer 1

GIVEN:-

$\frac{ \sqrt{sec \theta - 1} }{ \sqrt{sec \theta \: + 1} } + \frac{ \sqrt{sec \theta + 1} }{ \sqrt{sec \theta \: - 1} } = 2cosec \theta$

__________________________

TO FIND:-

PROVE THE IDENTITY.

__________________________

SOLUTION:-

(IN THE ATTACHMENT)

$\bullet \sf Trigonometric Values \\\\\\ \boxed{\begin{array}{c|c|c|c|c|c} \sf Angle & 0^{\circ} & 30^{\circ} & 45^{\circ} & 60^{\circ} & 90^{\circ} \\ \cline{1-6} \sin \theta & 0 & \dfrac{1}{2} & \dfrac{1}{\sqrt{2}} & \dfrac{\sqrt{3}}{2} & 1 \\ \cline{1-6} \cos \theta & 1 & \dfrac{\sqrt{3}}{2} & \dfrac{1}{\sqrt{2}} & \dfrac{1}{2} & 0 \\ \cline{1-6} \tan\theta & 0 & \dfrac{1}{\sqrt{3}} & 1 & \sqrt{3} & \textsf{Not D{e}fined}\end{array}}$