sec theta(1-sin theta)(sec theta +tan theta)
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Answered by
93
=secA(1-sinA)(secA+tanA)
=secA(secA+tanA-sinAsecA-sinAtanA)
=1/cosA[1/cosA+sinA/cosA-sinA/cosA-sin²A/cosA]
=1/cosA[1/cosA-sin²A/cosA]
=1/cosA[(1-sin²A)/cosA]
=1/cosA[cos²A/cosA]
=1
=secA(secA+tanA-sinAsecA-sinAtanA)
=1/cosA[1/cosA+sinA/cosA-sinA/cosA-sin²A/cosA]
=1/cosA[1/cosA-sin²A/cosA]
=1/cosA[(1-sin²A)/cosA]
=1/cosA[cos²A/cosA]
=1
Answered by
87
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