sec theta =13/12, find other trigonometric ratios
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Sec¢ = 13/12 = H/B
Hypotenuse = 13 , Base = 12
By Pythagoras theroem ,
( H )² = (B )² + ( P )²
( 13)² = ( 12)² + ( P )²
P² = 169 - 144
P = √25
P = 5
Therefore,
Sin¢ = P/H = 5/13
Cos ¢ = B/H = 12/13
Tan¢ = P/B = 12/5
Sec¢ = H/B = 13/12
Cosec¢ = H/P = 13/5
And,
Cot¢ = B/P = 5/12
Hypotenuse = 13 , Base = 12
By Pythagoras theroem ,
( H )² = (B )² + ( P )²
( 13)² = ( 12)² + ( P )²
P² = 169 - 144
P = √25
P = 5
Therefore,
Sin¢ = P/H = 5/13
Cos ¢ = B/H = 12/13
Tan¢ = P/B = 12/5
Sec¢ = H/B = 13/12
Cosec¢ = H/P = 13/5
And,
Cot¢ = B/P = 5/12
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