Sec theta=2x , y tan theta = 2 find the value of 2 (x power2 -1/y power 2)
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sec theta=2x
x=sec theta/2
y tan theta=2
y=2/tan theta
now put the values of x and y in the given eq
2 {(sec theta/2)^2 - 1/(2/tan theta)^2}
2 {(sec theta)^2/4 - (tan theta)^2/4}
2 {1+(tan theta)^2 - (tan theta)^2}/4
2 {(1+0)}/4
1/2
hence solved
hope it help you..
x=sec theta/2
y tan theta=2
y=2/tan theta
now put the values of x and y in the given eq
2 {(sec theta/2)^2 - 1/(2/tan theta)^2}
2 {(sec theta)^2/4 - (tan theta)^2/4}
2 {1+(tan theta)^2 - (tan theta)^2}/4
2 {(1+0)}/4
1/2
hence solved
hope it help you..
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