Math, asked by RSUNKALP, 10 months ago

Sec theta + cos theta =1 then sec ^3 + cos^3

Answers

Answered by harikairuvuru
1

Answer:

sec³ \theta+cos³ \theta=-2

Step-by-step explanation:

Given sec\theta +cos \theta=1  ⇒sec\theta +cos \theta-1=0  -->(1)

if x+y+z=0 then x³+y³+z³=3xyz

By above equation eq(1) can be written as

sec³ \theta+cos³ \theta+(-1)³=3(sec \theta)(cos  \theta)(-1)

sec³ \theta+cos³ \theta=-3+1                                    

sec³ \theta+cos³ \theta=-2

Answered by therock3704y
0

Answer:

copycat sunkalp ,you are asking questions during exam

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