Math, asked by dogloverbuddy2005, 7 months ago

sec theta - cos theta =1 then tan^2 theta /2 please help I will give brainliest

Answers

Answered by abrar6105khan

6

consider they as A

secA - cosA =1

1/cosA-cosA=1

(1-cos^2A)/cosA=1

sin^2A/cosA

sinA sinA/cosA

sinA tanA

tanA=1/sinA

tanA=cosecA

Squaring both sides

tan^2A=cosec^2A

dividing both sides by 2

tan^2A/2=cosec^2A/2

tan^2A/2=1/2sin^2A

HOPE IT WILL HELP YOU

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