Sec theta + cos theta = 2 then what is the value of sin^2 theta + tan^2 theta
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Let theta = x.
sec x+tan x = 2…………………..(1)
We know that :-
(sec x-tan x ) (sec x+tan x) = 1.
(sec x-tan x) (2) =1.
sec x-tan x = 1/2……………………..(2)
on adding and subtracting eq.(1) & (2).
2sec x= 5/2 => sec x = 5/4.
2tan x = 3/2 => tan x = 3/4.
sin x × 1/cos x = 3/4 .
sin x× sec x =3/4.
sin x × 5/4 = 3/4 .
sin x = 3/5 .Answer.
sec x+tan x = 2…………………..(1)
We know that :-
(sec x-tan x ) (sec x+tan x) = 1.
(sec x-tan x) (2) =1.
sec x-tan x = 1/2……………………..(2)
on adding and subtracting eq.(1) & (2).
2sec x= 5/2 => sec x = 5/4.
2tan x = 3/2 => tan x = 3/4.
sin x × 1/cos x = 3/4 .
sin x× sec x =3/4.
sin x × 5/4 = 3/4 .
sin x = 3/5 .Answer.
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