(sec theta +cos theta) (sec theta+cos theta)=tan 2theta +sin2 theta
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Actually there is a correction in ur question...,,,
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Step-by-step explanation:(sec A + cos A) ( sec A + cos A) = tan 2 A +sin 2 A
= sec^2A + cos ^2 A
= 1 - tan^2A + 1-sin^2A
= 1 GETS CANCEL ON BOTH THE SIDES...
= tan^2 A = tanA and tanA= tan 2 A
= sin^2 A = sinA and sin A = SIN 2 A
therefore ( sec A+ cos A) ( sec A + cos A) + TAN 2 A + SIN 2 A
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