Question

(sec theta+ cosec theta)(sin theta + cos theta) = 2+ sec theta.cosec theta

Answer 1

Answer:

Step-by-step explanation:

1) convert sec to 1/cos and cosec to 1/sin.

2)perform LCM You get  (1/cos +1/sin)(sin + cos)..

3)then ..( sin square + cos square + 2 cos x sin )/sin x cos

4) finally LHS = 1+2 cos x sin/ sin x cos

5)on RHS  convert sec to 1/cos and cosec to 1/sin..

6)  you get , 2+( 1/sin x cos )

7)perform LCM , so RHS= 1+2 cos x sin/ sin x cos