Question

sec theta minus cos theta equals to 2 then sec square theta minus cos square theta equal to

Answer 1

Answer:

hiii...

how are you???

here is your answer...

SecQ - cos Q = 5

Squaring both sides

(SecQ - cosQ) ^2 = 5^2

Sec^2Q + cos^2Q - 2 • secQ • cosQ = 25

Sec^2Q + cos^2Q -2 • 1/cosQ • cosQ = 25 { { secQ = 1/cosQ} }

Sec^2Q + cos^2Q -2 = 25

Sec^2Q + cos^2Q = 23

i hope it will help u...

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Answer 2

Answer:

I forgot to write several things

Let me mention them here

When we have obtained Sec²∅ +Cos²∅ = 6

Then we can write it as

Sec²∅+ Cos²∅ + 2Sec∅Cos∅ - 2Sec∅Cos∅= 6

Because When we add and subtract the same number then there is no effect on the answer

Woah, bro it took me some time, but I'm quite hopeful that this would help you with your doubt.

Also, can you mark this the Brainliest ? Thanks.