Math, asked by chinni640, 10 months ago

sec theta plus tan theta =1/2 then sec theta -tan theta=​

Answers

Answered by IamIronMan0
1

Answer:

 \huge\red{\{ \sec( \alpha )   -  \tan( \alpha ) \}  = 2}

We know

 \sec {}^{2} ( \alpha )  -   \tan {}^{2} ( \alpha )  = 1 \\  \\   \{ \sec( \alpha )  + \tan( \alpha ) \}    \{\sec( \alpha )   - \tan( \alpha )  \} = 1 \\  \\ \{ \sec( \alpha )   -  \tan( \alpha ) \}  =  \frac{1}{\{ \sec( \alpha )  + \tan( \alpha ) \} }  \\  \\ \{ \sec( \alpha )   -  \tan( \alpha ) \}  =  \frac{1}{ \frac{1}{2} }  = 2

Answered by umiko28
4

Answer:

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Step-by-step explanation:

here given sec¢ - tan¢ = 1

As you know that sec²¢ - tan²¢ = 1

so, sec²- tan²¢ = (sec¢ + tan¢ )( sec¢ - tan¢ )= 1

=>but (sec¢ + tan¢ ) = 2 ( given )

so.. 2 ( sec¢ - tan¢ ) = 1

sec¢ - tan¢ = 1/2 Answer

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