sec (-theta)=secant theta (or) -secant theta ??
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Step-by-step explanation:
sec(-A) = 1/cos(-A)
As you know, cosine of -ve is not differ from that of +ve.
Implies, sec(-A) = 1/cos(-A) = 1/cosA = secA
Answered by
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Answer:
I don't understand.......
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