(sec theta +tan theta) (1-sin theta)=cos theta
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Answer:
(secθ+tanθ)(1−sinθ),
=(1cosθ+sinθcosθ)(1−sinθ),
=(1+sinθcosθ)(1−sinθ1),
=1−sin2θcosθ,
=cos2θcosθ,
=cosθ
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