sec theta + tan theta -1/tan theta- sec theta +1=cos theta/1-sin theta
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plz add the image of question.
prernaraj:
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question plz
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L.H.S
= sec + tan - 1/tan-sec+1
=sec+tan-(sec^2-tan^2)/tan-sec+1
=sec+tan-(sec-tan)(sec+tan)/tan-sec+1
=(sec+tan)(1-sec+tan)/(tan-sec+1)
=sec+tan
=1/cos+sin/cos
=1+sin/cos
=(1+sin)(1-sin)/(1-sin)×cos. {multiplied 1-sin
up and down}
=1-sin^2/cos×(1-sin)
=cos^2/cos×(1-sin)
=cos/(1-sin). [ PROOVED]
= sec + tan - 1/tan-sec+1
=sec+tan-(sec^2-tan^2)/tan-sec+1
=sec+tan-(sec-tan)(sec+tan)/tan-sec+1
=(sec+tan)(1-sec+tan)/(tan-sec+1)
=sec+tan
=1/cos+sin/cos
=1+sin/cos
=(1+sin)(1-sin)/(1-sin)×cos. {multiplied 1-sin
up and down}
=1-sin^2/cos×(1-sin)
=cos^2/cos×(1-sin)
=cos/(1-sin). [ PROOVED]
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