Question

sec theta - tan theta =1bysec theta + tan theta​

Answer 1

Step-by-step explanation:

RHS

$\frac{1}{ \sec\theta + \tan \theta }$

Multiplying and dividing

$\sec \theta - \tan \theta \:$

$\frac{ \sec \theta - \tan \theta }{ (\sec \theta + \tan \theta)( \sec \theta - \tan \theta ) }$

$\frac{ \sec \theta - \tan\theta }{ { \sec }^{2} \theta - { \tan }^{2} \theta }$

$\sec\theta - \tan \theta$

LHS

Because Sec²©-tan²©=1

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