Math, asked by shreyaa18, 1 year ago

(sec theta -tan theta )*2 is 1-sin theta/1+sin theta

Answers

Answered by Anonymous

3

Step-by-step explanation:

We have , RHS =(1-sin A)/(1+sinA)= (1-sinA)(1-sinA)/(1+sinA)(1-sinA)

= (1-sinA)^2/(1-sin^2A)

=(1-sinA)^2/cos^2A

=(1/cosA -sinA/cosA)^2

=(secA - tanA)^2

=LHS

Hence , proved

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