sec theta +tan theta =2 then sec theta - tan theta = ?
Answers
Answered by
7
HELLO DEAR,
we know that:-
(sec²theta-tan²theta)=1-----(1)
now,
sectheta + tantheta =2
[ Multiply both side by (sectheta-tantheta)]
We get,
(Sectheta+tantheta) (sectheta-tantheta) = 2( sectheta-tantheta)
=> Sec²theta-tan²theta = 2(sectheta-tantheta)-------using (1)
=> 1=2( sectheta-tantheta)
=> Sectheta-tantheta=1/2
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:-
(sec²theta-tan²theta)=1-----(1)
now,
sectheta + tantheta =2
[ Multiply both side by (sectheta-tantheta)]
We get,
(Sectheta+tantheta) (sectheta-tantheta) = 2( sectheta-tantheta)
=> Sec²theta-tan²theta = 2(sectheta-tantheta)-------using (1)
=> 1=2( sectheta-tantheta)
=> Sectheta-tantheta=1/2
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
6
Hey !!
here given sec¢ - tan¢ = 1
As you know that sec²¢ - tan²¢ = 1
so, sec²- tan²¢ = (sec¢ + tan¢ )( sec¢ - tan¢ )= 1
=>but (sec¢ + tan¢ ) = 2 ( given )
so.. 2 ( sec¢ - tan¢ ) = 1
sec¢ - tan¢ = 1/2 Answer
hope it helps !!
#Rajukumar111
here given sec¢ - tan¢ = 1
As you know that sec²¢ - tan²¢ = 1
so, sec²- tan²¢ = (sec¢ + tan¢ )( sec¢ - tan¢ )= 1
=>but (sec¢ + tan¢ ) = 2 ( given )
so.. 2 ( sec¢ - tan¢ ) = 1
sec¢ - tan¢ = 1/2 Answer
hope it helps !!
#Rajukumar111
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