Question

sec theta + tan theta = 5/2 then what is the value of sec theta minus tan theta
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Answer 1

$\huge\underline\bold\red{★Answer★}$

$sec \alpha + tan \alpha = \frac{5}{2} \\ we \: know \: \: {sec}^{2} \alpha - {tan}^{2} \alpha = 1 \\ (sec \alpha - tan \alpha )(sec \alpha + tan \alpha ) = 1 \\ (sec \alpha - tan \alpha ) \frac{5}{2} = 1 \\ sec \alpha - tan \alpha = \frac{1}{ \frac{5}{2} } = \frac{2}{5}$