Question

sec theta-tan theta = 5
Cosec theta-Cot theta=3 then
(sec theta+tan theta) (cosec theta+ Cot theta)​ give u brainlist

Answer 1

Answer:

1/15

Step-by-step explanation:

secθ-tanθ = 5   & cosecθ-cotθ=3

we know sec²θ-tan²θ = 1

   => (secθ+tanθ)(secθ-tanθ)=1

   => secθ+tanθ = 1/(secθ-tanθ) = 1/5  -------------- (1)

similarly,

        cosecθ+cotθ = 1/3                       ---------------(2)

then,

(secθ+tanθ)(cosecθ+cotθ) = (1/5)*(1/3)          -------------->  by (1)&(2)

                                            = (1/15)