Sec (theta)-tan (theta)=a+1/a-1 , find cos(theta)=?
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Since, Sec∆=1/cos∆
& Tan∆ = Sin∆/Cos∆
Sec∆-Tan∆=(1/cos∆)-(Sin∆/Cos∆)
a+1/a-1=(1-Sin∆) /Cos∆
There fore cos∆ = a-1.
Where ∆ = theta.
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