Question

sec theta + tan theta = cos theta / 1 - sin theta ​

Answer 1

Answer:

(cos@/1-sin@)(1+sin@/1+sin@)

cos@+sin@cos@/1-sin'2@

cos@+sin@cos@/cos'2@

cos@/cos'2@+sin@cos@/cos'2@

1/cos@+sin@/cos@

sec@+tan@