Sec theta +tan theta =cos theta\1-sin theta
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Answered by
44
Answer:
L.H.S= secΘ + tan Θ
R.H.S= cosΘ/ 1- sin Θ
taking R.H.S= cosΘ/ 1- sinΘ
multiplying numerator and denominator by (1+ sinΘ)
cosΘ (1+ sinΘ)/ (1- sinΘ) (1 + sinΘ)
cosΘ + cosΘsinΘ / 1 - sin^2Θ
cosΘ + cosΘsinΘ / cos^2 Θ
i.e. cosΘ/ cos^2 + cosΘsinΘ/ cos^2Θ
=> 1 / cosΘ + sinΘ / cosΘ
= secΘ = tan Θ = L.H.S
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