sec theta + tan theta = cos theta / 1-sin theta solve ut by RHS
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Solving through RHS:
Divide and multiply by 1 + sinA:
=> cosA/(1 - sinA) × (1 + sinA)/(1 + sinA)
=> cosA(1 + sinA) / (1 - sinA)(1 + sinA)
=> cosA(1 + sinA) / (1 - sin²A)
=> cosA(1 + sinA) / cos²A
=> (1 + sinA) / cosA
=> (1/cosA) + (sinA/cosA)
=> secA + tanA , where A = theta.
Proved.
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