Question

sec theta + tan theta= p find p square -1 upon p square +1



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Answer 1

Answer:

here is your answer

Step-by-step explanation:

hope it helps u

Answer 2

Step-by-step explanation:

p = sec x + tan x

p² - 1 = (sec x + tan x)² - 1

=> sec² x + tan²x + 2 tan x sec x - 1

=> sec² x - 1 + tan² x + 2 tan x sec x

=> tan² x + tan ²x + 2 tan x sec x

=> 2 tan² x + 2 tan x sec x .........1

p² + 1 = sec² x + tan² x + 2 sec x tan x + 1

=> sec² x + tan² x + 1 + 2 sec x tan x

=> sec² x + sec² x + 2 sec x tan x........2

=> 2 sec² x + 2sec x tan x

now (1)/(2)

=> (2 tan² x + 2 sec x tan x)/(2 sec² x + 2 sec x tan x )

=> [2 tan x ( tan x + sec x)]/[ 2 sec x ( sec x + tan x)]

=> (2 tan x) / (2 sec x) [ tan x + sec x cancels out ]

=> tan x / sec x

=> (sin x / cos x) / (1/cos x)

=> [sin x / cos x] × [cos x/1]

=> sin x [ cos x cancels out ]