sec theta +tan theta = P prove that p^2-1/p^2+1=sin theta
Answers
Answered by
8
hope this will help you
Attachments:
sneha198:
thanks
Answered by
6
Hey there !!
From LHS -
p² -1 / p² + 1 = ( secⲫ + tanⲫ ) - 1 / ( secⲫ + tanⲫ)² + 1
=> sec²Ⲫ + tan² + 2secⲪtanⲪ - 1 / sec²Ⲫ + tan² + 2secⲪtanⲪ + 1
=> ( sec². ⲫ - 1) + tan ² + 2sec ⲫtanⲫ / secⲫ ² + 2 secⲫ tanⲫ + ( 1 + tanⲫ. ²)
=> tan² ⲫ + tan² ⲫ + 2sec. ⲫ tan ⲫ/ sec.²ⲫ + 2 secⲫ tanⲫ + sec.² ⲫ
=> 2tan. ² ∅ + 2tan∅sec∅ / 2 sec∅²+ 2sec∅ tan∅
=> 2tan∅ ( tan∅ + sec∅) / 2 sec∅( sec∅+ tan∅)
=> tan∅/ sec∅
=> sin∅ / cos∅ . sec∅
=> sin∅ ➣ RHS
Proved
Hope this would help you !!
From LHS -
p² -1 / p² + 1 = ( secⲫ + tanⲫ ) - 1 / ( secⲫ + tanⲫ)² + 1
=> sec²Ⲫ + tan² + 2secⲪtanⲪ - 1 / sec²Ⲫ + tan² + 2secⲪtanⲪ + 1
=> ( sec². ⲫ - 1) + tan ² + 2sec ⲫtanⲫ / secⲫ ² + 2 secⲫ tanⲫ + ( 1 + tanⲫ. ²)
=> tan² ⲫ + tan² ⲫ + 2sec. ⲫ tan ⲫ/ sec.²ⲫ + 2 secⲫ tanⲫ + sec.² ⲫ
=> 2tan. ² ∅ + 2tan∅sec∅ / 2 sec∅²+ 2sec∅ tan∅
=> 2tan∅ ( tan∅ + sec∅) / 2 sec∅( sec∅+ tan∅)
=> tan∅/ sec∅
=> sin∅ / cos∅ . sec∅
=> sin∅ ➣ RHS
Proved
Hope this would help you !!
Similar questions
Hindi,
7 months ago
Social Sciences,
7 months ago
Math,
7 months ago
Geography,
1 year ago
Social Sciences,
1 year ago
Art,
1 year ago