Question

Sec theta + tan theta = R, then (R ^ 2 - 1 + 2R)/(R ^ 2 + 1)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\huge\orange{Answer}$

We have,

secθ+ tanθ= x

(secθ−tanθ)

(secθ+tanθ)(secθ−tanθ)

=x

(secθ−tanθ)

(sec

2

θ−tan

2

θ)

=

x

We know that

sec 2

tan 2

1

Therefore,

(secθ−tanθ)

1

=

x

secθ− tanθ=

x

1

On adding the equation (1) and (2), we get

2secθ= x+

x

1

2secθ=

x

x 2

secθ=

2x

x 2

Hence, this is the answer.