Math, asked by siddhimohite765, 1 month ago

(sec theta + tan theta) × ( sec theta - tan) =?​

Answers

Answered by rrrrrtryrutu
0

Answer:

ahn-udxg-nef

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I am alo.ne

telugu

Step-by-step explanation:

ahn-udxg-nef

girl.s can joi.n

I am alo.ne

telugu

Answered by tennetiraj86
0

Step-by-step explanation:

Given:-

( Sec θ + Tan θ ) ( Sec θ - Tan θ)

To find:-

Find the value of ( Sec θ + Tan θ ) ( Sec θ - Tan θ)

Solution:-

Given that

( Sec θ + Tan θ ) ( Sec θ - Tan θ)

It is in the form of (a+b)(a-b)

Where,

a = Sec θ

b = Tan θ

We know that

(a+b)(a-b) = a^2 - b^2

( Sec θ + Tan θ ) ( Sec θ - Tan θ)

=> ( Sec θ)^2 - ( Tan θ)^2

=> Sec^2 θ - Tan^2 θ

We know that

Sec^2 A - Tan^2 A = 1

=>Sec^2 θ - Tan^2 θ = 1

Answer:-

( Sec θ + Tan θ ) ( Sec θ - Tan θ) = 1

Used formulae:-

  • (a+b)(a-b) = a^2 - b^2

  • Sec^2 A - Tan^2 A = 1
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