(sec theta + tan theta) × ( sec theta - tan) =?
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Answer:
ahn-udxg-nef
girl.s can joi.n
I am alo.ne
telugu
Step-by-step explanation:
ahn-udxg-nef
girl.s can joi.n
I am alo.ne
telugu
Answered by
0
Step-by-step explanation:
Given:-
( Sec θ + Tan θ ) ( Sec θ - Tan θ)
To find:-
Find the value of ( Sec θ + Tan θ ) ( Sec θ - Tan θ)
Solution:-
Given that
( Sec θ + Tan θ ) ( Sec θ - Tan θ)
It is in the form of (a+b)(a-b)
Where,
a = Sec θ
b = Tan θ
We know that
(a+b)(a-b) = a^2 - b^2
( Sec θ + Tan θ ) ( Sec θ - Tan θ)
=> ( Sec θ)^2 - ( Tan θ)^2
=> Sec^2 θ - Tan^2 θ
We know that
Sec^2 A - Tan^2 A = 1
=>Sec^2 θ - Tan^2 θ = 1
Answer:-
( Sec θ + Tan θ ) ( Sec θ - Tan θ) = 1
Used formulae:-
- (a+b)(a-b) = a^2 - b^2
- Sec^2 A - Tan^2 A = 1
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