sec theta-tan theta÷ sec theta +tan theta =1/4 ..find sin theta
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10
(1/cos theta -sin theta/cos theta)/1/cos theta +sin theta/cos theta=1/4
;(1-sin theta/cos theta)/1+sin theta/cos theta=1/4
;1-sin theta/1+sin theta=1/4
;4-4sin theta=1+sin theta
;-5sin theta=1-4
;sin theta=-3/-5
;sin theta=3/5
;(1-sin theta/cos theta)/1+sin theta/cos theta=1/4
;1-sin theta/1+sin theta=1/4
;4-4sin theta=1+sin theta
;-5sin theta=1-4
;sin theta=-3/-5
;sin theta=3/5
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30
hey frien.. here your answer with solution please see in the picture
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